`C_(2) H_(5) Cl` + `KCN` `rarr "X " overset("Hydroysis")(rarr) `Y, 'X' and 'Y' are:

Options

A. `C_(2) H_(6) and C_(2) H_(5)`CN
B. `C_(2)H_(5)`CN and `C_(2)H_(6)`
C. `C_(2)H_(5)`CN and `C_(2)H_(5)CH_(2)NH_(2)`
D. `C_(2)H_(5)`CN and `C_(2)H_(5)`COOH

Answer

To solve the question, we need to identify the products 'X' and 'Y' formed from the reaction of ethyl chloride (C₂H₅Cl) with potassium cyanide (KCN), followed by hydrolysis.

### Step 1: Identify the reactants
The reactants in this reaction are:
- Ethyl chloride (C₂H₅Cl)
- Potassium cyanide (KCN)

### Step 2: Understand the reaction mechanism
Ethyl chloride contains a chlorine atom that is electronegative. This creates a partial positive charge on the carbon atom, making it an electrophilic center. The cyanide ion (CN⁻) from potassium cyanide acts as a nucleophile due to its partial negative charge.

### Step 3: Nucleophilic substitution reaction
When KCN reacts with ethyl chloride, the nucleophile (CN⁻) attacks the electrophilic carbon atom in ethyl chloride, leading to the substitution of the chlorine atom. The reaction can be represented as follows:

\[ \text{C}_2\text{H}_5\text{Cl} + \text{KCN} \rightarrow \text{C}_2\text{H}_5\text{CN} + \text{KCl} \]

Here, the product formed is propanenitrile (C₂H₅CN), which we will denote as 'X'.

### Step 4: Hydrolysis of the nitrile
Next, we perform hydrolysis on the product 'X' (propanenitrile). Hydrolysis of a nitrile typically involves converting it to an amide and then to a carboxylic acid. The reaction can be summarized as follows:

1. Hydrolysis of propanenitrile (C₂H₅CN) leads to propanamide (C₂H₅CONH₂).
2. Further hydrolysis of propanamide results in propanoic acid (C₂H₅COOH).

Thus, the final product 'Y' after hydrolysis is propanoic acid.

### Step 5: Summarize the products
- Product 'X' is propanenitrile (C₂H₅CN).
- Product 'Y' is propanoic acid (C₂H₅COOH).

### Conclusion
The final answer is:
- X = Propanenitrile (C₂H₅CN)
- Y = Propanoic acid (C₂H₅COOH)