Which of the following is a correct statement?:

Options

A. `C_(2)H_(5)`Br reacts with alco. KOH to give `C_(2)H_(5)`OH
B. Reaction of `C_(2)H_(5)` Br with metallic Na gives ethane
C. `C_(2)H_(5)` Br reacts with sodium ethoxide to give ether
D. `C_(2)H_(5)`Br reacts with AgCN to give ethyl cyanide

Answer

To solve the question, we need to analyze each of the four statements regarding the reactions of ethyl bromide (C2H5Br) with different reagents and determine which statement is correct.

### Step-by-Step Solution:

1. **Analyze the First Statement:**
- **Statement:** Ethyl bromide reacts with alcoholic KOH to give ethyl alcohol (ethanol).
- **Reaction:** Ethyl bromide (C2H5Br) reacts with alcoholic KOH, which is a strong base. This reaction leads to elimination (beta dehydrohalogenation), resulting in the formation of ethene (C2H4) and not ethyl alcohol.
- **Conclusion:** This statement is **incorrect**.

2. **Analyze the Second Statement:**
- **Statement:** Reaction of ethyl bromide with metallic sodium gives ethane.
- **Reaction:** The Wurtz reaction involves the reaction of alkyl halides with sodium metal, leading to the formation of higher alkanes. In this case, two moles of ethyl bromide would react with two moles of sodium to produce butane (C4H10), not ethane (C2H6).
- **Conclusion:** This statement is **incorrect**.

3. **Analyze the Third Statement:**
- **Statement:** Ethyl bromide reacts with sodium ethoxide to give ether.
- **Reaction:** Ethyl bromide reacts with sodium ethoxide (C2H5O-Na+) through a nucleophilic substitution mechanism. The ethoxide ion attacks the electrophilic carbon in ethyl bromide, resulting in the formation of diethyl ether (C2H5-O-C2H5) and sodium bromide as a byproduct.
- **Conclusion:** This statement is **correct**.

4. **Analyze the Fourth Statement:**
- **Statement:** Ethyl bromide reacts with silver cyanide to give ethyl cyanide.
- **Reaction:** Silver cyanide (AgCN) is a covalent compound. When ethyl bromide reacts with it, the nitrogen atom of the cyanide can attack the electrophilic carbon, leading to the formation of ethyl isocyanate (C2H5-N=C=O) instead of ethyl cyanide (C2H5-CN).
- **Conclusion:** This statement is **incorrect**.

### Final Conclusion:
After analyzing all four statements, the only correct statement is the third one: **Ethyl bromide reacts with sodium ethoxide to give ether.**