The product of the reaction of chloromethane with sodium sulphide is

Options

A. Dimethyl sulphide
B. Methan thiol
C. Mixture of both the above
D. None of the above

Answer

To determine the product of the reaction between chloromethane (CH3Cl) and sodium sulfide (Na2S), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are chloromethane (CH3Cl) and sodium sulfide (Na2S).

2. **Understand the Reaction Type**:
- Sodium sulfide (Na2S) is a source of sulfide ions (S^2-). When an alkyl halide (like chloromethane) reacts with sodium sulfide, it undergoes a nucleophilic substitution reaction.

3. **Write the General Reaction**:
- The general reaction for an alkyl halide (R-X) with sodium sulfide (Na2S) can be represented as:
\[ R-X + Na2S \rightarrow R-S-R + 2NaX \]
- Here, R represents the alkyl group, and X is the halogen.

4. **Substitute the Reactants**:
- For chloromethane (CH3Cl), the alkyl group (R) is CH3, and the halogen (X) is Cl.
- Therefore, substituting into the general reaction gives:
\[ CH3Cl + Na2S \rightarrow CH3-S-CH3 + 2NaCl \]

5. **Identify the Product**:
- The product formed is dimethyl sulfide (CH3-S-CH3), which is a thioether. The byproducts are sodium chloride (NaCl).

6. **Final Balanced Equation**:
- The balanced equation for the reaction is:
\[ CH3Cl + Na2S \rightarrow CH3-S-CH3 + 2NaCl \]

### Conclusion:
- The product of the reaction of chloromethane with sodium sulfide is **dimethyl sulfide (CH3-S-CH3)**.