Acetone ` underset("Dry ether")overset(CH_(3)MgI)to" intermediate " overset(H_(2)O)to ` 'X' . Here, [X] is :

Options

A. `CH_(3) OH`
B. `CH_(3)-CH_(2)-OH`
C. `CH_(3)-CH(OH)-CH_(3)`
D. `(CH_(3))_(2)C(OH)(CH_(3))`

Answer

To solve the problem, we will follow the steps of the reaction involving acetone and Grignard reagent (CH₃MgI) in dry ether, and then the subsequent reaction with water.

### Step-by-Step Solution:

1. **Identify the Reactants:**
- The reactant is acetone (CH₃COCH₃) and the Grignard reagent is methylmagnesium iodide (CH₃MgI).

2. **Formation of the Intermediate:**
- Acetone is a carbonyl compound, and the carbonyl carbon is electrophilic. The Grignard reagent (CH₃MgI) contains a nucleophilic methyl group (CH₃⁻).
- The nucleophilic methyl group (CH₃⁻) attacks the carbonyl carbon of acetone, leading to the formation of a tetrahedral intermediate. The reaction can be represented as:
\[ \text{CH}_3\text{COCH}_3 + \text{CH}_3\text{MgI} \rightarrow \text{(CH}_3)_2\text{C(OH)(CH}_3)\text{MgI}^- \]
- This intermediate is a magnesium alkoxide.

3. **Hydrolysis of the Intermediate:**
- The next step involves hydrolysis of the intermediate when it reacts with water (H₂O). The hydrolysis will convert the alkoxide into an alcohol.
- The reaction can be represented as:
\[ \text{(CH}_3)_2\text{C(OH)(CH}_3)\text{MgI}^- + \text{H}_2\text{O} \rightarrow \text{(CH}_3)_3\text{C(OH)} + \text{MgI}^+ \]
- The product formed after hydrolysis is tert-butyl alcohol (t-butanol), which is represented as (CH₃)₃COH.

4. **Final Answer:**
- Therefore, the final product \( [X] \) is tert-butyl alcohol (t-butanol).

### Conclusion:
The correct answer for the question is tert-butyl alcohol.

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