Methanol on heating with salicylic acid and cond . `H_(2) SO_(4)` gives :

Options

A. Formalin
B. Vinegar
C. Oil of winter green
D. None of these

Answer

To solve the question, "Methanol on heating with salicylic acid and concentrated H₂SO₄ gives:", we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are Methanol (CH₃OH) and Salicylic Acid (C₇H₆O₃), which contains both a hydroxyl (-OH) group and a carboxylic acid (-COOH) group.

2. **Recognize the Reaction Type**:
- The reaction between an alcohol and a carboxylic acid in the presence of an acid catalyst (concentrated H₂SO₄) is known as esterification. This process forms an ester and water.

3. **Write the Esterification Reaction**:
- The hydroxyl group (-OH) from the carboxylic acid (salicylic acid) and a hydrogen atom (H) from the alcohol (methanol) will combine to form water (H₂O). The remaining parts will combine to form the ester.
- The reaction can be represented as:
\[ \text{Salicylic Acid (C₇H₆O₃) + Methanol (CH₃OH)} \rightarrow \text{Methyl Salicylate (C₇H₆O₄)} + \text{H₂O} \]

4. **Identify the Product**:
- The product formed from this reaction is Methyl Salicylate (C₇H₆O₄), which is also known as "Oil of Wintergreen".

5. **Final Answer**:
- Therefore, the final answer is that Methanol on heating with Salicylic Acid and concentrated H₂SO₄ gives Methyl Salicylate (Oil of Wintergreen).