The oxidation product of 2-propanol with hot conc. `HNO_(3)` is :

Options

A. Ethanoic acid
B. Propanone
C. Propanal
D. None of these

Answer

To determine the oxidation product of 2-propanol (also known as isopropanol) when treated with hot concentrated nitric acid (HNO3), we follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of 2-Propanol**:
- 2-propanol is a secondary alcohol with the molecular formula C3H8O. Its structure can be represented as:
```
CH3
|
CH - OH
|
CH3
```

2. **Understand the Nature of the Oxidizing Agent**:
- Hot concentrated HNO3 is a strong oxidizing agent. However, it is not the strongest oxidizer, which means it will not fully oxidize secondary alcohols to carboxylic acids but will convert them to ketones.

3. **Oxidation of Secondary Alcohol**:
- When a secondary alcohol is oxidized, it typically forms a ketone. In the case of 2-propanol, the oxidation will yield propanone (commonly known as acetone).
- The reaction can be represented as:
```
CH3-CHOH-CH3 (2-propanol) → CH3-CO-CH3 (propanone)
```

4. **Conclusion**:
- Therefore, the oxidation product of 2-propanol with hot concentrated HNO3 is propanone (acetone).

### Final Answer:
The oxidation product of 2-propanol with hot concentrated HNO3 is **propanone**.

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