Identify X in the reaction ` HCHO + CH_(3)Mgloverset("dry ether")to "Intermediate" overset(H_(2) "O"//H^(+)) to X ` :

Options

A. `CH_(3) OH`
B. `CH_(3) CH_(2) OH`
C. `CH_(3) COCH_(3)`
D. `CH_(3)OCH_(3)`

Answer

To identify the compound X in the reaction given, we will follow the steps of the reaction involving formaldehyde (HCHO) and methylmagnesium iodide (CH3MgI) in dry ether, followed by hydrolysis in acidic conditions.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- We have formaldehyde (HCHO) and methylmagnesium iodide (CH3MgI). The Grignard reagent (CH3MgI) contains a methyl group (CH3) and a magnesium iodide (MgI) part.

2. **Nucleophilic Addition Reaction**:
- The Grignard reagent acts as a nucleophile. The methyl group (CH3-) from CH3MgI attacks the electrophilic carbon of the carbonyl group (C=O) in formaldehyde (HCHO).
- This leads to the formation of a tetrahedral intermediate.

3. **Formation of the Intermediate**:
- The reaction can be represented as:
\[ HCHO + CH3MgI \rightarrow H2C(OH)(CH3)MgI \]
- Here, the carbonyl oxygen becomes negatively charged (alkoxide), and the magnesium iodide stabilizes this negative charge.

4. **Hydrolysis of the Intermediate**:
- The intermediate formed is then subjected to hydrolysis in the presence of water (H2O) and an acid (H+).
- During hydrolysis, the alkoxide (O-) is protonated, and the bond between the carbon and magnesium iodide is cleaved.
- This results in the formation of ethanol (ethyl alcohol) and magnesium iodide hydroxide (Mg(OH)I):
\[ H2C(OH)(CH3)MgI + H2O \rightarrow CH3CH2OH + Mg(OH)I \]

5. **Final Product (X)**:
- The final product X is identified as ethanol (CH3CH2OH).

### Conclusion:
Thus, the compound X formed in this reaction is **ethanol (C2H5OH)**.