`CH_(3) MgBr overset(X) to "Intermediate" overset(H_(3) O^(+))to ` 1 - propanol, x in the reaction is :

Options

A. Formaldehyde
B. Propanol
C. Oxirane
D. Ethanal

Answer

To solve the problem, we need to identify the intermediate (X) that reacts with the Grignard reagent CH₃MgBr to ultimately yield 1-propanol after hydrolysis with H₃O⁺.

### Step-by-Step Solution:

1. **Identify the Product**: The final product is 1-propanol (C₃H₈O), which has the structure CH₃-CH₂-CH₂OH. This indicates that we need a total of three carbon atoms in the final product.

2. **Determine the Contribution of the Grignard Reagent**: The Grignard reagent CH₃MgBr contributes one carbon atom (from CH₃) to the final product. Therefore, we need an intermediate that provides the remaining two carbon atoms.

3. **Identify the Type of Reaction**: Grignard reagents react with carbonyl compounds to form alcohols. Since we need to form a primary alcohol (1-propanol), the carbonyl compound must be an aldehyde.

4. **Select the Appropriate Carbonyl Compound**: The simplest aldehyde that can provide the necessary two carbon atoms is ethyl aldehyde (acetaldehyde, CH₃CHO). When CH₃MgBr reacts with CH₃CHO, it will add the CH₃ group to the carbonyl carbon.

5. **Write the Reaction**:
- The reaction can be represented as:
\[ CH₃MgBr + CH₃CHO \rightarrow \text{Intermediate} \]
- The intermediate formed will be a magnesium alkoxide.

6. **Hydrolysis of the Intermediate**: Upon hydrolysis with H₃O⁺, the intermediate will yield 1-propanol:
\[ \text{Intermediate} + H₃O^+ \rightarrow CH₃-CH₂-CH₂OH \]

7. **Conclusion**: Therefore, the intermediate (X) in this reaction is acetaldehyde (CH₃CHO).

### Final Answer:
The value of X in the reaction is acetaldehyde (CH₃CHO).