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C(6)H(5) OH and C(6) H(5) COOH show dif...

`C_(6)H_(5) OH and C_(6) H_(5) COOH` show difference in the reaction with

A

`NaHCO_(3)`

B

Na metal

C

NaOH

D

Litmus paper

Text Solution

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The correct Answer is:
To differentiate between phenol (C₆H₅OH) and benzoic acid (C₆H₅COOH), we can use sodium bicarbonate (NaHCO₃) as a reagent. Here’s a step-by-step solution to demonstrate the difference in their reactions: ### Step 1: Understanding the Compounds - **Phenol (C₆H₅OH)**: It is a weak acid. - **Benzoic Acid (C₆H₅COOH)**: It is a stronger acid compared to phenol. ### Step 2: Reaction with Sodium Bicarbonate - **Sodium Bicarbonate (NaHCO₃)**: This is a mild base that reacts with strong acids to produce carbon dioxide (CO₂) gas. ### Step 3: Reaction of Benzoic Acid with Sodium Bicarbonate 1. When benzoic acid reacts with sodium bicarbonate, the following reaction occurs: \[ \text{C}_6\text{H}_5\text{COOH} + \text{NaHCO}_3 \rightarrow \text{C}_6\text{H}_5\text{COO}^- \text{Na}^+ + \text{H}_2\text{O} + \text{CO}_2 \uparrow \] 2. In this reaction, carbon dioxide gas is evolved, which can be observed as effervescence. ### Step 4: Reaction of Phenol with Sodium Bicarbonate 1. When phenol reacts with sodium bicarbonate, there is no significant reaction: \[ \text{C}_6\text{H}_5\text{OH} + \text{NaHCO}_3 \rightarrow \text{No Reaction} \] 2. Since phenol is a weaker acid, it does not react with sodium bicarbonate to produce carbon dioxide. ### Step 5: Conclusion - **Observation**: The evolution of CO₂ gas when benzoic acid reacts with NaHCO₃ indicates that it is a stronger acid than phenol, which does not produce any gas when reacted with NaHCO₃. - **Differentiation**: Thus, we can differentiate between phenol and benzoic acid using sodium bicarbonate; benzoic acid will produce effervescence while phenol will not.
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