What is the product formed in the following reaction ?
`C_(6)H_(5)OH+C Cl_(4) underset((ii)H_(3)O^(+))overset((i)NaOH)to`

Options

A. Benzaldehyde
B. Salicylaldehyde
C. p-Hydroxybenzoic acid
D. o-Hydroxybenzoic acid

Answer

To solve the problem, we will analyze the reaction step by step.

### Step 1: Identify the Reactants
The reactants in the given reaction are:
- Phenol (C₆H₅OH)
- Carbon tetrachloride (CCl₄)
- Sodium hydroxide (NaOH)
- Hydronium ion (H₃O⁺)

### Step 2: Understand the Reaction Mechanism
Phenol will react with carbon tetrachloride in the presence of sodium hydroxide. This reaction typically involves the formation of a phenoxide ion (C₆H₅O⁻) when phenol reacts with NaOH.

### Step 3: Formation of Phenoxide Ion
When phenol (C₆H₅OH) reacts with NaOH, it forms the phenoxide ion:
\[ C₆H₅OH + NaOH \rightarrow C₆H₅O^{-}Na^{+} + H₂O \]

### Step 4: Reaction with Carbon Tetrachloride
The phenoxide ion can then react with carbon tetrachloride (CCl₄). The chlorine atoms in CCl₄ can be substituted by the phenoxide ion, leading to the formation of a chlorinated product. However, in this case, we are interested in the final product after further reactions.

### Step 5: Hydrolysis of the Intermediate
The product formed from the reaction of the phenoxide ion with CCl₄ will undergo hydrolysis. This means that when we treat the intermediate with water (or H₃O⁺), it will lead to the formation of a carboxylic acid.

### Step 6: Final Product Formation
After hydrolysis, the final product formed is ortho-hydroxybenzoic acid (salicylic acid):
\[ C₆H₄(OH)COOH \]

### Conclusion
The product formed in the reaction is ortho-hydroxybenzoic acid (salicylic acid).

### Final Answer:
**Ortho-hydroxybenzoic acid (salicylic acid)**

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