Addition of borane to 1-butene following by oxidative alkaline hydrolysis gives :

Options

A. n-butyl alcohol
B. Sec. butyl alcohol
C. isobutyl alcohol
D. ter. Butyl alcohol

Answer

To solve the problem of what product is formed when borane is added to 1-butene followed by oxidative alkaline hydrolysis, we can follow these steps:

### Step 1: Understand the Reactants
1-butene is an alkene with the structure CH2=CH-CH2-CH3. It has a double bond between the first and second carbon atoms.

### Step 2: Hydroboration Reaction
When borane (BH3) is added to 1-butene, the reaction proceeds via hydroboration. The alkene acts as a nucleophile and attacks the boron atom, which is a Lewis acid. The double bond donates its electrons to boron, forming a cyclic intermediate.

### Step 3: Formation of Organoborane
In the hydroboration step, boron adds to the less substituted carbon atom (the terminal carbon in this case), leading to the formation of an organoborane intermediate. The structure of the organoborane formed will be:
- CH3-CH2-CH2-CH2-BH2

### Step 4: Oxidative Hydrolysis
Next, we perform oxidative alkaline hydrolysis. This involves treating the organoborane with hydrogen peroxide (H2O2) in the presence of a base (NaOH). During this step, the boron atom is replaced by a hydroxyl group (–OH).

### Step 5: Final Product Formation
The final product after oxidative hydrolysis will be n-butyl alcohol (CH3-CH2-CH2-CH2-OH).

### Conclusion
Thus, the addition of borane to 1-butene followed by oxidative alkaline hydrolysis gives n-butyl alcohol.

### Final Answer
**N-butyl alcohol (CH3-CH2-CH2-CH2-OH)**

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