The reaction of `CH_(3) Mgl` with acetone and hydrolysis of the resulting product gives :

Options

A. `CH_(3) CH_(2) CH_(2) OH`
B. `CH_(3) CH_(2) CH_(2) CH_(2) OH`
C. `(CH_(3))_(2) CHOH`
D. `(CH_(3))_(3) COH`

Answer

To solve the problem of what product is formed when CH₃MgI (a Grignard reagent) reacts with acetone and is subsequently hydrolyzed, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The Grignard reagent is CH₃MgI.
- The other reactant is acetone, which has the formula CH₃COCH₃.

2. **Understand the Mechanism**:
- The carbonyl carbon in acetone (C=O) is electrophilic due to the partial positive charge on it, while the methyl group (CH₃) in the Grignard reagent acts as a nucleophile because it has a partial negative charge.

3. **Nucleophilic Attack**:
- The nucleophilic CH₃ from the Grignard reagent attacks the electrophilic carbon of the carbonyl group in acetone. This forms a tetrahedral intermediate:
\[ \text{CH}_3\text{C(OH)(CH}_3)\text{(MgI)}^+ \]

4. **Formation of the Alkoxide Intermediate**:
- The tetrahedral intermediate can be represented as:
\[ \text{CH}_3\text{C(OH)(CH}_3)\text{(MgI)}^+ \]
- Here, the oxygen becomes negatively charged (alkoxide ion).

5. **Hydrolysis**:
- When this intermediate is hydrolyzed (reacted with water), the MgI part is removed, and the alkoxide ion is converted into an alcohol:
\[ \text{CH}_3\text{C(OH)(CH}_3) + \text{H}_2\text{O} \rightarrow \text{CH}_3\text{C(OH)(CH}_3) + \text{Mg(OH)I} \]

6. **Final Product**:
- The final product is a tertiary alcohol, specifically:
\[ \text{(CH}_3)_3\text{COH} \]
- This compound is known as tert-butanol.

7. **Conclusion**:
- The final product after the reaction and hydrolysis is (CH₃)₃COH, which corresponds to option number 4.

### Final Answer:
The product formed is **(CH₃)₃COH** (tert-butanol).

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