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A 20 W light source emits monochromatic ...

A 20 W light source emits monochromatic light of wavelength 600 nm the number of photons ejected per second in the form of avogardro 's number will be

A

`N_(A)`

B

`10^(-2)N_(A)`

C

`10^(-4)N_(A)`

D

`10^(-6)N_(A)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of photons emitted per second by a 20 W light source emitting monochromatic light of wavelength 600 nm, we can follow these steps: ### Step 1: Calculate the energy of a single photon The energy \( E \) of a single photon can be calculated using the formula: \[ E = \frac{hc}{\lambda} \] where: - \( h \) (Planck's constant) = \( 6.626 \times 10^{-34} \, \text{J s} \) - \( c \) (speed of light) = \( 3 \times 10^8 \, \text{m/s} \) - \( \lambda \) (wavelength) = \( 600 \, \text{nm} = 600 \times 10^{-9} \, \text{m} \) Substituting the values: \[ E = \frac{(6.626 \times 10^{-34} \, \text{J s})(3 \times 10^8 \, \text{m/s})}{600 \times 10^{-9} \, \text{m}} \] ### Step 2: Perform the calculation Calculating the above expression: \[ E = \frac{(6.626 \times 3) \times 10^{-26}}{600 \times 10^{-9}} = \frac{19.878 \times 10^{-26}}{600 \times 10^{-9}} = \frac{19.878}{600} \times 10^{-17} \approx 3.313 \times 10^{-19} \, \text{J} \] ### Step 3: Calculate the total energy emitted per second The total power \( P \) of the light source is given as 20 W, which means it emits 20 Joules of energy per second. ### Step 4: Calculate the number of photons emitted per second The number of photons \( N \) emitted per second can be calculated using the formula: \[ N = \frac{P}{E} \] Substituting the values: \[ N = \frac{20 \, \text{J/s}}{3.313 \times 10^{-19} \, \text{J}} \approx 6.03 \times 10^{20} \, \text{photons/s} \] ### Step 5: Convert to Avogadro's number Avogadro's number \( N_A \) is approximately \( 6.022 \times 10^{23} \). To express the number of photons in terms of Avogadro's number: \[ \text{Number of photons in terms of } N_A = \frac{N}{N_A} = \frac{6.03 \times 10^{20}}{6.022 \times 10^{23}} \approx 10^{-3} \, N_A \] ### Final Answer Thus, the number of photons emitted per second in terms of Avogadro's number is: \[ 10^{-3} \, N_A \]
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