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The total number of nodal planes present...

The total number of nodal planes present in the third shell will be

A

7

B

11

C

13

D

14

Text Solution

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The correct Answer is:
To determine the total number of nodal planes present in the third shell (n=3), we first need to understand the relationship between the principal quantum number (n) and the azimuthal quantum number (l), which defines the shape of the orbitals. ### Step-by-Step Solution: 1. **Identify the Principal Quantum Number (n)**: - For the third shell, the principal quantum number \( n \) is 3. 2. **Determine the Azimuthal Quantum Number (l)**: - The azimuthal quantum number \( l \) can take values from 0 to \( n-1 \). Therefore, for \( n = 3 \): \[ l = 0, 1, 2 \] - This corresponds to the following orbitals: - \( l = 0 \) corresponds to the s orbital (3s) - \( l = 1 \) corresponds to the p orbital (3p) - \( l = 2 \) corresponds to the d orbital (3d) 3. **Count the Nodal Planes for Each Orbital**: - The number of nodal planes in an orbital is equal to the azimuthal quantum number \( l \): - For 3s (\( l = 0 \)): - Nodal planes = 0 - For 3p (\( l = 1 \)): - Nodal planes = 1 - For 3d (\( l = 2 \)): - Nodal planes = 2 4. **Calculate the Total Number of Nodal Planes**: - Now, we sum the nodal planes from each type of orbital: \[ \text{Total nodal planes} = \text{Nodal planes from 3s} + \text{Nodal planes from 3p} + \text{Nodal planes from 3d} \] \[ = 0 + 1 + 2 = 3 \] ### Final Answer: The total number of nodal planes present in the third shell is **3**. ---
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