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The temperature at which ice will begin ...

The temperature at which ice will begin to separate from a mixture of 20 mass percent of glycol `(C_(2)H_(6)O_(2))` in water, is : [`K_(f)` (water) = 1.86 K kg `mol^(-1)`]

A

280.5 K

B

265. 5K

C

276.5 K

D

269.5 K

Text Solution

AI Generated Solution

The correct Answer is:
To determine the temperature at which ice will begin to separate from a mixture of 20 mass percent glycol (C₂H₆O₂) in water, we can follow these steps: ### Step 1: Understand the given data - Mass percent of glycol = 20% - Therefore, in 100 g of solution, the mass of glycol = 20 g and the mass of water (solvent) = 100 g - 20 g = 80 g. - Kf (cryoscopic constant for water) = 1.86 K kg mol⁻¹. ### Step 2: Calculate the molar mass of glycol The molar mass of glycol (C₂H₆O₂) can be calculated as follows: - Carbon (C): 12 g/mol × 2 = 24 g/mol - Hydrogen (H): 1 g/mol × 6 = 6 g/mol - Oxygen (O): 16 g/mol × 2 = 32 g/mol - Total molar mass of glycol = 24 + 6 + 32 = 62 g/mol. ### Step 3: Calculate the number of moles of glycol Using the mass of glycol: - Moles of glycol = mass of glycol / molar mass of glycol. - Moles of glycol = 20 g / 62 g/mol = 0.3226 mol. ### Step 4: Calculate the molality of the solution Molality (m) is defined as the number of moles of solute per kilogram of solvent: - Mass of water = 80 g = 0.08 kg. - Molality (m) = moles of glycol / mass of water in kg = 0.3226 mol / 0.08 kg = 4.0325 mol/kg. ### Step 5: Calculate the depression in freezing point (ΔTf) Using the formula for depression in freezing point: \[ \Delta T_f = i \cdot K_f \cdot m \] Where: - i (van 't Hoff factor) = 1 (since glycol is a non-electrolyte). - Kf = 1.86 K kg mol⁻¹. - m = 4.0325 mol/kg. Now calculate ΔTf: \[ \Delta T_f = 1 \cdot 1.86 \cdot 4.0325 = 7.5 K \] ### Step 6: Calculate the freezing point of the solution The normal freezing point of water is 0 °C (273 K). The freezing point of the solution will be: \[ \text{Freezing point} = 0 °C - \Delta T_f \] \[ \text{Freezing point} = 0 °C - 7.5 °C = -7.5 °C \] Convert this to Kelvin: \[ \text{Freezing point in Kelvin} = 273 K - 7.5 K = 265.5 K \] ### Final Answer The temperature at which ice will begin to separate from the mixture is **265.5 K**. ---
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