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In the reaction C(2)H(5)OH + " HX " over...

In the reaction `C_(2)H_(5)OH + " HX " overset(ZnX_(2))(rarr) C_(2)H_(5)X,` the order of the reactivity of HX is :

A

HBr `gt` HI `gt` HCl

B

HI `gt` HCl `gt` HBr

C

HI `gt` HBr `gt` HCl

D

HCl `gt` HBr `gt` HI

Text Solution

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The correct Answer is:
To determine the order of reactivity of HX in the reaction \( C_2H_5OH + HX \overset{ZnX_2}{\rightarrow} C_2H_5X \), we need to analyze the reactivity of different hydrogen halides (HX) with ethanol (C2H5OH). ### Step-by-Step Solution: 1. **Identify the Reaction Type**: The reaction is a nucleophilic substitution where the hydroxyl group (OH) of ethanol is replaced by a halogen (X) from HX. The presence of ZnX2 facilitates this substitution. **Hint**: Understand that nucleophilic substitution involves replacing one group with another, in this case, OH is replaced by a halogen. 2. **Consider the Halogens**: The halogens involved can be fluorine (F), chlorine (Cl), bromine (Br), and iodine (I). The hydrogen halides we are considering are HCl, HBr, and HI. **Hint**: Recall the halogens' positions in the periodic table and their properties, particularly their bond strengths. 3. **Evaluate Bond Strength**: The bond strength of HX decreases as we move down the group in the periodic table: - H-F bond is the strongest. - H-Cl bond is weaker than H-F. - H-Br bond is weaker than H-Cl. - H-I bond is the weakest. **Hint**: The weaker the bond, the easier it is to dissociate and release the halide ion (X⁻). 4. **Analyze Reactivity**: - **HI**: The bond between H and I is the weakest, making it the most reactive. The iodine ion (I⁻) can easily participate in the nucleophilic substitution. - **HBr**: The bond is stronger than HI but weaker than HCl, making it less reactive than HI but more reactive than HCl. - **HCl**: The bond is the strongest among the three, making it the least reactive in this context. **Hint**: Remember that the ease of reaction is related to how easily the halide ion can be generated from the hydrogen halide. 5. **Determine the Order of Reactivity**: Based on the bond strengths and the ability to generate halide ions, the order of reactivity of HX is: \[ HI > HBr > HCl \] **Hint**: Think about how the size of the halogen affects the bond strength and the ability to act as a nucleophile. ### Final Answer: The order of reactivity of HX in the given reaction is: \[ \text{HI} > \text{HBr} > \text{HCl} \]
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