The compound formed by the reaction of ethyl chloride with a sodium-lead alloy at 400°C is:

Options

A. Tetraethyl lead
B. Sodium ethoxide
C. Ethyl sodium
D. No reaction

Answer

To determine the compound formed by the reaction of ethyl chloride with a sodium-lead alloy at 400°C, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant is ethyl chloride, which has the chemical formula C2H5Cl.
- The other reactant is a sodium-lead alloy, which consists of sodium (Na) and lead (Pb) but is not chemically combined.

2. **Understand the Reaction Conditions**:
- The reaction takes place at a high temperature of 400°C. This temperature is significant as it can facilitate the reaction between ethyl chloride and sodium.

3. **Determine the Reaction Process**:
- Sodium will react with ethyl chloride to form ethyl radicals (C2H5) and sodium chloride (NaCl).
- The lead in the alloy acts as a catalyst and does not participate in the reaction directly.

4. **Write the Balanced Reaction**:
- The balanced reaction can be represented as:
\[ 4 \text{C}_2\text{H}_5\text{Cl} + 4 \text{Na} \rightarrow 4 \text{NaCl} + \text{C}_2\text{H}_5\text{Pb} \text{ (Tetraethyl Lead)} \]
- This indicates that 4 moles of ethyl chloride react with 4 moles of sodium to produce tetraethyl lead (C2H5)4Pb and sodium chloride.

5. **Identify the Product**:
- The product formed is tetraethyl lead, commonly abbreviated as TEL. It is known for its use as an anti-knocking agent in gasoline.

6. **Conclusion**:
- Therefore, the compound formed by the reaction of ethyl chloride with a sodium-lead alloy at 400°C is tetraethyl lead (TEL).

### Final Answer:
The compound formed is tetraethyl lead (TEL).