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What is the product formed in the follow...

What is the product formed in the following reaction?
`C_(6)H_(5)OH + "CCl"_(4) overset("NaOH")(rarr)`

A

Benzaldehyde

B

Salicyladehyde

C

p-Hydroxybenzoic acid

D

o-Hydroxybenzoic acid

Text Solution

AI Generated Solution

The correct Answer is:
To determine the product formed in the reaction of phenol (C₆H₅OH) with carbon tetrachloride (CCl₄) in the presence of sodium hydroxide (NaOH), we can follow these steps: ### Step 1: Identify the Reactants The reactants in this reaction are: - Phenol (C₆H₅OH) - Carbon tetrachloride (CCl₄) - Sodium hydroxide (NaOH) ### Step 2: Understand the Role of NaOH Sodium hydroxide acts as a base in this reaction. It will deprotonate phenol to form phenoxide ion (C₆H₅O⁻). ### Step 3: Formation of Phenoxide Ion When phenol reacts with NaOH, the hydroxyl group (–OH) loses a hydrogen ion (H⁺), resulting in the formation of the phenoxide ion: \[ \text{C₆H₅OH} + \text{NaOH} \rightarrow \text{C₆H₅O}^- + \text{Na}^+ + \text{H₂O} \] ### Step 4: Reaction of Phenoxide Ion with CCl₄ The phenoxide ion (C₆H₅O⁻) can now react with carbon tetrachloride (CCl₄). The negatively charged oxygen in the phenoxide ion can attack the carbon atom in CCl₄, leading to the substitution of one of the chlorine atoms. ### Step 5: Nucleophilic Substitution The nucleophilic attack by the phenoxide ion on CCl₄ results in the formation of a chlorinated compound. This step can be represented as: \[ \text{C₆H₅O}^- + \text{CCl₄} \rightarrow \text{C₆H₅O-CCl₃} + \text{Cl}^- \] ### Step 6: Hydrolysis of the Chlorinated Compound The chlorinated compound (C₆H₅O-CCl₃) can undergo hydrolysis in the presence of NaOH. The chlorine atoms can be replaced by hydroxyl groups (–OH) through nucleophilic substitution: \[ \text{C₆H₅O-CCl₃} + 3 \text{NaOH} \rightarrow \text{C₆H₅O-C(OH)₃} + 3 \text{NaCl} \] ### Step 7: Final Product Formation The final product after the hydrolysis will be ortho-hydroxybenzoic acid (salicylic acid), where the hydroxyl group (–OH) is at the ortho position relative to the carboxylic acid group (–COOH): \[ \text{C₆H₅(OH)(COOH)} \] ### Conclusion The product formed in this reaction is ortho-hydroxybenzoic acid (salicylic acid).
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