H-C `equiv` C - H + 2HCl `rarr`Final product, final product will be:

Options

A.
B. `CH_(2) = `CHCl
C. `underset(Cl)underset(|)(CH_(2)) - underset(Cl)(underset(|)(CH_(2))`
D. none of these

Answer

To solve the question regarding the reaction of acetylene (C≡C) with 2 moles of HCl, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants are acetylene (C≡C) and 2 moles of HCl.

2. **First Addition of HCl**:
When acetylene reacts with the first mole of HCl, it undergoes an electrophilic addition reaction. The triple bond (C≡C) is broken, and one H atom from HCl will attach to one of the carbon atoms while the Cl atom will attach to the other carbon atom. Since acetylene is symmetrical, the addition does not follow Markovnikov's rule.

- **Intermediate Product**:
The product after the first addition will be vinyl chloride (CH2=CHCl).

3. **Second Addition of HCl**:
Now, we add the second mole of HCl to the intermediate product (CH2=CHCl). This time, the addition will follow Markovnikov's rule because we have an asymmetrical alkene (vinyl chloride). The Cl- will attach to the carbon with fewer hydrogen atoms.

- **Final Product Formation**:
The Cl- will attach to the carbon that already has one Cl atom (the carbon of the vinyl group), and H+ will attach to the other carbon. This results in the formation of 1,1-dichloroethane.

- **Final Product**:
The final product is CH3CHCl2.

4. **Conclusion**:
The final product after the complete reaction of acetylene with 2 moles of HCl is CH3CHCl2.

### Final Answer:
The final product will be **CH3CHCl2**.

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