Ethyl bromide reacts with lead sodium alloy to form:

Options

A. Tetra ethyl lead
B. Tetra ethyl bromide
C. Both (1) and (2)
D. none of these

Answer

To solve the question of what compound is formed when Ethyl Bromide reacts with Lead Sodium Alloy, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant is Ethyl Bromide, which has the chemical formula CH₃CH₂Br.

2. **Understand the Reaction**:
- Ethyl Bromide will react with Lead Sodium Alloy, which can be represented as NaPb (sodium-lead alloy).

3. **Determine the Reaction Products**:
- When Ethyl Bromide reacts with Lead Sodium Alloy, it undergoes a reaction that typically involves the formation of a lead compound. In this case, the product formed is Tetraethyl Lead.

4. **Write the Chemical Equation**:
- The reaction can be represented as:
\[ 4 \text{ CH}_3\text{CH}_2\text{Br} + 4 \text{ NaPb} \rightarrow \text{ (CH}_3\text{CH}_2\text{)}_4\text{Pb} + 4 \text{ NaBr} \]
- Here, Tetraethyl Lead is represented as (C₂H₅)₄Pb or CH₃CH₂ whole 4 Pb.

5. **Final Product**:
- The final product of the reaction is Tetraethyl Lead (C₂H₅)₄Pb.

### Conclusion:
The compound formed when Ethyl Bromide reacts with Lead Sodium Alloy is **Tetraethyl Lead**.

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