The correct order of C–X bond polarity is:

Options

A. `CH_(3) Br gt CH_(3) Cl gt CH_(3) l`
B. `CH_(3)l gt CH_(3) Br gt CH_(3) `Cl
C. `CH_(3) Cl gt CH_(3) Br gt CH_(3)`I
D. `CH_(3) Cl gt CH_(3) I gt CH_(3)` Br

Answer

To determine the correct order of C–X bond polarity, we need to consider the electronegativity of the halogens involved. The bond polarity is influenced by the difference in electronegativity between carbon (C) and the halogen (X). The greater the difference in electronegativity, the more polar the bond will be.

### Step-by-Step Solution:

1. **Identify the Halogens**: The halogens we are considering are chlorine (Cl), bromine (Br), and iodine (I).

2. **Understand Electronegativity**: Electronegativity is a measure of an atom's ability to attract and hold onto electrons. The electronegativity values for the halogens are approximately:
- Chlorine (Cl): 3.16
- Bromine (Br): 2.96
- Iodine (I): 2.66

3. **Determine Electronegativity Differences**: The polarity of the C–X bond can be assessed by looking at the electronegativity differences:
- For C–Cl: Difference = 3.16 (Cl) - 2.55 (C) = 0.61
- For C–Br: Difference = 2.96 (Br) - 2.55 (C) = 0.41
- For C–I: Difference = 2.66 (I) - 2.55 (C) = 0.11

4. **Rank the Bonds by Polarity**: Based on the electronegativity differences calculated:
- C–Cl has the highest polarity (0.61)
- C–Br has moderate polarity (0.41)
- C–I has the lowest polarity (0.11)

5. **Write the Correct Order**: Therefore, the correct order of C–X bond polarity from most polar to least polar is:
- C–Cl > C–Br > C–I

### Final Answer:
The correct order of C–X bond polarity is: **C–Cl > C–Br > C–I**.