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The compound with highest boiling point ...

The compound with highest boiling point is

A

Ethylene bromide

B

Ethylene chloride

C

Ethylidene bromide

D

Ethylidene chloride

Text Solution

AI Generated Solution

The correct Answer is:
To determine which compound has the highest boiling point among the given haloalkanes, we will analyze the molecular weights and the structure of each compound. Here’s a step-by-step solution: ### Step 1: Identify the Compounds The compounds we are comparing are: 1. 1,2-Dibromoethane (Ethylene bromide) 2. 1,2-Dichloroethane 3. 1,1-Dibromoethane 4. 1,1-Dichloroethane ### Step 2: Analyze Molecular Weights Molecular weight plays a crucial role in determining boiling points. The higher the molecular weight, the higher the boiling point due to stronger van der Waals forces. - **1,2-Dibromoethane (C2H4Br2)**: - Molecular weight = (2 × 12) + (4 × 1) + (2 × 80) = 24 + 4 + 160 = 188 g/mol - **1,2-Dichloroethane (C2H4Cl2)**: - Molecular weight = (2 × 12) + (4 × 1) + (2 × 35.5) = 24 + 4 + 71 = 99 g/mol - **1,1-Dibromoethane (C2H4Br2)**: - Molecular weight = (2 × 12) + (4 × 1) + (2 × 80) = 188 g/mol (same as 1,2-Dibromoethane) - **1,1-Dichloroethane (C2H4Cl2)**: - Molecular weight = (2 × 12) + (4 × 1) + (2 × 35.5) = 99 g/mol (same as 1,2-Dichloroethane) ### Step 3: Compare the Molecular Weights From the calculations: - 1,2-Dibromoethane: 188 g/mol - 1,2-Dichloroethane: 99 g/mol - 1,1-Dibromoethane: 188 g/mol - 1,1-Dichloroethane: 99 g/mol ### Step 4: Consider the Structure and Surface Area The boiling point is also influenced by the structure of the compounds: - **Branched vs. Unbranched**: Branched compounds generally have lower boiling points due to decreased surface area, which affects van der Waals forces. - **1,2-Dibromoethane** is unbranched, while **1,1-Dibromoethane** is branched. ### Step 5: Conclusion Since both 1,2-Dibromoethane and 1,1-Dibromoethane have the same molecular weight, we need to consider their structure. The unbranched structure of 1,2-Dibromoethane provides a larger surface area, leading to stronger van der Waals forces compared to the branched 1,1-Dibromoethane. Thus, **1,2-Dibromoethane (Ethylene bromide)** has the highest boiling point among the given compounds. ### Final Answer The compound with the highest boiling point is **1,2-Dibromoethane (Ethylene bromide)**. ---
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