The number of alkanols and ethers represented by the molecular formulae `C_(3) H_(8) O and C_(4) H_(10) O` respectively are gives by the set :

Options

A. 2,1 , 3,2
B. 1, 2 , 2,3
C. 2,1 , 4,3
D. 2,1 , 3,4

Answer

To determine the number of alkanols and ethers represented by the molecular formulas C₃H₈O and C₄H₁₀O, we will analyze each compound step by step.

### Step 1: Analyze C₃H₈O
1. **Identify the number of carbon atoms (C)**: There are 3 carbon atoms.
2. **Identify the number of hydrogen atoms (H)**: There are 8 hydrogen atoms.
3. **Identify the number of oxygen atoms (O)**: There is 1 oxygen atom.

### Step 2: Determine the types of alkanols (alcohols) possible
1. **Primary Alcohols**:
- CH₃CH₂OH (propan-1-ol)
2. **Secondary Alcohols**:
- CH₃CHOHCH₃ (propan-2-ol)

Thus, for C₃H₈O, we can have **2 alkanols**: propan-1-ol and propan-2-ol.

### Step 3: Determine the types of ethers possible
1. **Ethers**: The simplest ether with this formula is:
- CH₃CH₂OCH₃ (dimethyl ether)

Thus, for C₃H₈O, we can have **1 ether**: dimethyl ether.

### Step 4: Analyze C₄H₁₀O
1. **Identify the number of carbon atoms (C)**: There are 4 carbon atoms.
2. **Identify the number of hydrogen atoms (H)**: There are 10 hydrogen atoms.
3. **Identify the number of oxygen atoms (O)**: There is 1 oxygen atom.

### Step 5: Determine the types of alkanols (alcohols) possible
1. **Primary Alcohols**:
- CH₃CH₂CH₂CH₂OH (butan-1-ol)
- CH₃CH₂CH(OH)CH₃ (butan-2-ol)
2. **Tertiary Alcohols**:
- CH₃C(OH)(CH₃)CH₂CH₃ (butan-2-ol)

Thus, for C₄H₁₀O, we can have **4 alkanols**: butan-1-ol, butan-2-ol, and 2-methylpropan-2-ol.

### Step 6: Determine the types of ethers possible
1. **Symmetrical Ethers**:
- CH₃CH₂OCH₂CH₃ (diethyl ether)
2. **Asymmetrical Ethers**:
- CH₃CH₂OCH₃ (methoxyethane)
- CH₃OCH₂CH₂CH₃ (methoxypropane)

Thus, for C₄H₁₀O, we can have **3 ethers**: diethyl ether, methoxyethane, and methoxypropane.

### Final Count
- For C₃H₈O: **2 alkanols and 1 ether**
- For C₄H₁₀O: **4 alkanols and 3 ethers**

### Summary
The final answer is:
- Alkanols: 2 (from C₃H₈O) and 4 (from C₄H₁₀O)
- Ethers: 1 (from C₃H₈O) and 3 (from C₄H₁₀O)