The oxidation product of 2-propanol with hot conc. `HNO_(3)` is :

Options

A. Ethanoic acid
B. Propanone
C. Propanal
D. None of these

Answer

To determine the oxidation product of 2-propanol (isopropanol) when treated with hot concentrated nitric acid (HNO₃), we can follow these steps:

### Step 1: Identify the structure of 2-propanol
2-propanol is a secondary alcohol with the molecular formula C₃H₈O. Its structure can be represented as:
```
CH₃
|
CH - OH
|
CH₃
```

### Step 2: Understand the oxidation process
When a secondary alcohol is oxidized, it typically converts to a ketone or a carboxylic acid. In the case of 2-propanol, the oxidation will lead to the formation of acetic acid (ethanoic acid) and carbon dioxide.

### Step 3: Reaction with hot concentrated HNO₃
When 2-propanol is oxidized with hot concentrated nitric acid, the oxidation process involves the removal of hydrogen atoms and the addition of oxygen. The reaction can be summarized as follows:
- 2-propanol (C₃H₈O) is oxidized to acetic acid (C₂H₄O₂) and carbon dioxide (CO₂).

### Step 4: Write the balanced equation
The balanced chemical equation for the oxidation of 2-propanol with concentrated HNO₃ can be represented as:
\[ C₃H₈O + HNO₃ \rightarrow C₂H₄O₂ + CO₂ + H₂O \]

### Step 5: Identify the final product
From the reaction, we can conclude that the primary oxidation product of 2-propanol when treated with hot concentrated nitric acid is acetic acid (ethanoic acid).

### Final Answer
The oxidation product of 2-propanol with hot concentrated HNO₃ is **acetic acid (ethanoic acid)**.

---