The element with atomic number 118 is likely to have the same outer shell configuration as an element with atomic number

Options

A. 18
B. 28
C. 58
D. 88

Answer

To solve the question, we need to determine the outer shell electron configuration of the element with atomic number 118 and find which of the given atomic numbers (18, 28, 58, or 88) has the same outer shell configuration.

### Step-by-Step Solution:

1. **Identify the Element with Atomic Number 118**:
- The element with atomic number 118 is Oganesson (Og).

2. **Determine the Electron Configuration of Oganesson**:
- The electron configuration can be built by filling the orbitals according to the Aufbau principle.
- The configuration for atomic number 118 is:
- 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d¹⁰ 6p⁶ 7s² 5f¹⁴ 6d¹⁰ 7p⁶
- This can be summarized as:
- [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁶ (where [Rn] is the electron configuration of Radon, atomic number 86).

3. **Identify the Valence Shell**:
- The outermost shell (valence shell) for Oganesson is the 7th shell (n=7).
- The valence shell configuration is 7s² 7p⁶.

4. **Check the Given Atomic Numbers**:
- We need to check the outer shell configurations of the elements with atomic numbers 18, 28, 58, and 88.

**For Atomic Number 18 (Argon)**:
- Configuration: 1s² 2s² 2p⁶ 3s² 3p⁶
- Valence shell: n=3 (not matching).

**For Atomic Number 28 (Nickel)**:
- Configuration: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁸
- Valence shell: n=4 (not matching).

**For Atomic Number 58 (Cerium)**:
- Configuration: [Xe] 6s² 4f¹
- Valence shell: n=6 (not matching).

**For Atomic Number 88 (Radium)**:
- Configuration: [Rn] 7s²
- Valence shell: n=7 (matches).

5. **Conclusion**:
- The element with atomic number 118 (Oganesson) has the same outer shell configuration as the element with atomic number 88 (Radium).

### Final Answer:
The element with atomic number 118 is likely to have the same outer shell configuration as the element with atomic number **88**.