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There are two isotopes of an element wit...

There are two isotopes of an element with atomic mass z. Heavier one has atomic mass z+2 and lighter one has z-1, then abundance of lighter one is

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Let the percentage of the lighter isotope be 'x' then the percentage of the heavier isotope will be `(1-x)`.
This means that, or which means that `(Z+2)(1-x)+(Z-1)x=Z or Z-Zx+2-2x+Zx-x=Z` which means that `x=(2)/(3)=0.666" ie "66.6%`
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