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0.05 g of a sample of KClO3 containing s...

0.05 g of a sample of `KClO_3` containing some KCl on decomposition liberated just sufficient oxygen for complete oxidation of 20 " mL of " CO. The volume of CO was measured at `27^@C` and 750 mm Hg. Calculate the perentage purity of `KClO_3`.

Text Solution

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`underset("20 ml")(CO)+underset("10 ml")((1)/(2)O_(2))rarr 2CO_(2)" Mass of oxygen "=(PV)/(RT)xx32=(0.9868xx0.01)/(0.0821xx300)xx32`
`"Now, "2KClO_(3)rarr 2KCl +3O_(2)" "=0.0128g`
`"Amount of "KClO_(3)" reacted "=(245)/(96)xx0.0128" So, % of "KClO_(3)" in the sample"`
`=0.0326g" "=(0.0326)/(0.05)xx100=65.33%`
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