Calculate the n-factor of reactants in the given reactions.
(a) `FeCr_(2)O_(4) rarr Fe^(3+)+Cr^(6+)`

Explanation

To calculate the n-factor of the reactant in the reaction \( \text{FeCr}_2\text{O}_4 \rightarrow \text{Fe}^{3+} + \text{Cr}^{6+} \), we need to analyze the changes in oxidation states of the elements involved.

### Step-by-Step Solution:

1. **Identify the Oxidation States:**
- In \( \text{FeCr}_2\text{O}_4 \):
- Iron (Fe) is in the +2 oxidation state.
- Chromium (Cr) is in the +3 oxidation state (since there are two chromium atoms, we will calculate their contribution).
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