Calculate the n-factor of reactants in the given reactions.
(d) `Fe(NO_(3))_(3)rarr Fe^(2+)+NO`

Explanation

To calculate the n-factor of the reactant \( \text{Fe(NO}_3\text{)}_3 \) in the reaction \( \text{Fe(NO}_3\text{)}_3 \rightarrow \text{Fe}^{2+} + \text{NO} \), we will follow these steps:

### Step 1: Identify the oxidation states
- In \( \text{Fe(NO}_3\text{)}_3 \), the oxidation state of iron (Fe) is +3.
- The oxidation state of nitrogen (N) in \( \text{NO}_3^- \) can be calculated as follows:
\[ X + 3(-2) = -1 \quad \Rightarrow \quad X - 6 = -1 \quad \Rightarrow \quad X = +5 \]
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