How many oxygen atoms are there in `2.5 g-`molecules of `K_(2)SO_(4).Al_(2)(SO_(4))_(3).24H_(2)O`?

Explanation

To find the number of oxygen atoms in 2.5 gram molecules of \( K_2SO_4 \cdot Al_2(SO_4)_3 \cdot 24H_2O \), we will follow these steps:

### Step 1: Identify the components of the compound
The compound is \( K_2SO_4 \cdot Al_2(SO_4)_3 \cdot 24H_2O \). We need to determine how many oxygen atoms are present in each part of this compound.

### Step 2: Count the oxygen atoms in \( K_2SO_4 \)
In \( K_2SO_4 \):
- There are 4 oxygen atoms.
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