If 5.6 litres of hydrogen and 22.4 litres of oxygen react in a vessel to form water then the mass of water formed will be?

Explanation

To solve the problem of determining the mass of water formed when 5.6 liters of hydrogen reacts with 22.4 liters of oxygen, we can follow these steps:

### Step 1: Convert the volumes of gases to moles
We know that at standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters.

- For hydrogen (H₂):
\[
\text{Moles of H₂} = \frac{5.6 \text{ L}}{22.4 \text{ L/mole}} = 0.25 \text{ moles}
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