What molarity of 30ml `Na_(2)S_(2)O_(3)` will be needed to completely neutralise 12.7 g of iodine?

Explanation

To find the molarity of 30 mL of Na₂S₂O₃ needed to completely neutralize 12.7 g of iodine (I₂), we will follow these steps:

### Step 1: Write the balanced chemical equation
The reaction between sodium thiosulfate (Na₂S₂O₃) and iodine (I₂) can be represented as:
\[ \text{Na}_2\text{S}_2\text{O}_3 + \text{I}_2 \rightarrow \text{Na}_2\text{S}_4\text{O}_6 + 2\text{NaI} \]

### Step 2: Determine the n-factor for iodine
Iodine (I₂) has an oxidation state of 0 in its elemental form and changes to -1 in NaI. The change in oxidation state for each iodine atom is:
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