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Myoglobin stores oxygen for metabolic pr...

Myoglobin stores oxygen for metabolic processes in muscle. Chemical analysis shows that it contains `0.34%` Fe by mass. Minimum molecular mass of myoglobin is

A

16470 gm

B

16176 gm

C

17500 gm

D

1647 gm

Text Solution

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The correct Answer is:
To find the minimum molecular mass of myoglobin, we can follow these steps: ### Step 1: Set up the equation Let the mass of myoglobin be \( x \) grams. According to the problem, myoglobin contains \( 0.34\% \) iron (Fe) by mass. Therefore, the mass of iron in myoglobin can be expressed as: \[ \text{Mass of Fe} = 0.34\% \times x = \frac{0.34}{100} \times x \] ### Step 2: Relate mass of iron to the number of iron atoms Let \( y \) be the number of iron atoms in myoglobin. The molar mass of iron (Fe) is approximately \( 56 \, \text{g/mol} \). Therefore, the total mass of iron in myoglobin can also be expressed as: \[ \text{Mass of Fe} = y \times 56 \, \text{g} \] ### Step 3: Set the two expressions for mass of iron equal Now we can set the two expressions for the mass of iron equal to each other: \[ \frac{0.34}{100} \times x = y \times 56 \] ### Step 4: Solve for \( x \) Rearranging the equation gives us: \[ x = \frac{y \times 56 \times 100}{0.34} \] ### Step 5: Minimize \( x \) To find the minimum molecular mass of myoglobin, we need to minimize \( x \). This occurs when \( y = 1 \) (i.e., there is one iron atom in myoglobin): \[ x = \frac{1 \times 56 \times 100}{0.34} \] ### Step 6: Calculate \( x \) Now we can calculate \( x \): \[ x = \frac{5600}{0.34} \approx 16470.59 \, \text{g/mol} \] ### Conclusion Thus, the minimum molecular mass of myoglobin is approximately \( 16470.59 \, \text{g/mol} \).
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