Home
Class 12
CHEMISTRY
Equivalent weight of N(2) in the change ...

Equivalent weight of `N_(2)` in the change
`N_(2) rarr NH_(3)` is

A

28/6

B

28

C

28/2

D

28/3

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

Equivalent weight of NH_(3) in the change N_(2)rarrNH_(3) is :

Equivalent weight of NH_(4)OH is

Assertion :- Equivalent weight of NH_(3) in the reaction N_(2) rarrNH_(3) is 17//3 while that of N_(2) is 28//6 . Reason :- "Equivalent weight" =("Molecular weight")/("number of "e^(-)" lost or gained/mole")

Equivalent weight of N_(2)H_(4) is

The equivalent weight of a species if acts as oxidant or reductant should be derived by : Eq. weight of oxidant or reductant = ("Mol. wt. of oxidant or reductant")/{("Number of electrons lost or gained by one"),("moleculae of oxidant or reductant"):} During chemical reactions, equal equivalents of one species react with same number of equivalents of other species giving same number of equivalent of products. However this is not true for reactants if they react in terms of moles. Also Molarity can be converted to normality by multiplying the molarity with valence factor or 'n' factor. Equivalent weight of N_(2) and NH_(3) in the change N_(2)rarrNH_(3) respectively is:

Equivalent weight of NH_(3) as a base is

What is the equivalent weight of NH_(3) in the given reaction? 3CuO+2NH_(3) rarr 3Cu+N_(2)+3H_(2)O

Equivalent weight of (NH_(4))_(2)Cr_(2)O_(7) in the changes is: (NH)_(4)Cr_(2)O_(7)rarrN_(2)+Cr_(2)O_(3)+4H_(2)O

What is the equivalent weight of HNO_(3) in the given reaction? 4Zn+10HNO_(3) rarr 4Zn(NO_(3))_(2)+NH_(4)NO_(3)+3H_(2)O

Equivalent weight and n-factor