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The wave number of the first line in the...

The wave number of the first line in the Balmer series of hydrogen atom is `15200 cm^(-1)`. What is the wave number of the first line in the Balmer series of `Be^(3+)`?

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`bar(v) = RZ^(2) ((1)/(n_(1)^(2))- (1)/(n_(2)^(2)))`, for H-atom, Z =1, for `Be^(3+)`, Z =4 and for first line of Balmer series `n_(1) =2 & n_(2) =3` therefore `bar(v)_(H) = R ((1)/(2^(2)) - (1)/(3^(2))) = 15200 cm^(-1)` (given)
and `bar(v)_(Be^(3+)) = R(4)^(2) ((1)/(2^(2)) - (1)/(3^(2))) = 15200 xx 16 cm^(-1) = 2.432 xx 10^(5) cm^(-1)`
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