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The angular momentum of electron in a ...

The angular momentum of electron in a Bohr's orbit of H atom is `4.2178 xx 10^(-34) kg m^(2)s^(-1)`. Calculate the wavelength of the spectral line when the electrton falls from this level to the next lower level.

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Given, mvr `= (nh)/(2pi) :. (nh)/(2pi) = 4.2178 xx 10^(-34)`
`:.` or `n = (4.2178 xx 10^(-34) xx 2 xx 3.14)/(6.625 xx 10^(-34)) = 4`
`:.` Thus, `(1)/(lamda) = R [(1)/(n_(1)^(2)) - (1)/(n_(2)^(2))]`
`:.` The transition spctral line for `4^(th)` to `3^(rd)` shrell is
`:. (1)/(lamda) = 109678 [(1)/(3^(2)) - (1)/(4^(2))]`
`:. 1.8 xx 10^(-4) cm`
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