Calculate the momentum of the particle w...

Calculate the momentum of the particle which has de Broglie wavelength `1"Ã…"(10^(-10)m)` and `h=6.6xx10^(-34)J-sec`.

Verified by Experts

`lamda = (h)/(p) or p = (h)/(lamda) = (6.626 xx 10^(-34) J.sec)/(10^(-10)m) = 6.626 xx 10^(-24) kg "m sec"^(-1)`

Similar Questions

Explore conceptually related problems

Calculate the momentum of a particle which has de Broglie wavelength of 2.5xx10^(-10)m .

Calculate the momentum of a particle which has a de Broglie wavelength of 10 nm

The momentum of a particle which has a de Broglie wavelength of 2.5 xx 10^-10 m is.

The momentum of a particle having a de-Broglie wavelength of 10^(17) m is (Given, h=6.625xx10^(-34)m )

Calculate the momentum of a particle which has a de Broglie wavelength of 2 Å,(h = 6.6 xx 10^(-34) kg m^(2) s^(-1))

The momentum of a paricle which has a d-Broglie wavelength of 0.1 nm is ( h= 6.6 xx10^(-34) J s)

Calculate the energy of an electron having de-Broglie wavelength 5500Å. Given, h=6.62xx10^(-34)Js, m_(e)=9.1xx10^(-31)kg .

The linear momentum of the particle is 6.63 kg m/s. Calculate the de Broglie wavelength.

The momentum of a photon of de Broglie wavelength 5000Å is …………… . [Plank's constant =6.63xx10^(-34)J.s ]