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Calculate the accelerating potential tha...

Calculate the accelerating potential that must be imparted to a proton beam to give it an effective wavelength of ` 0. 005 nm`.

Text Solution

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Let V be the potential to which proton beam is accelerated so that it starts moving at a velocity v
`eV = (1)/(2) mv^(2)`….(1)
Also, `lamda = (h)/(mv)`
`v = (h)/(m lamda)`….(2)
From (1) and (2)
`V = (h^(2))/(2me lamda^(2)) = ((6.62xx 10^(-34))^(2))/(2 xx 1.672 xx 10^(-27) xx 1.6 xx 10^(-19) (0.005 xx 10^(-9))^(2))`
=32.8V
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