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What will be the wavelength of radiation...

What will be the wavelength of radiation released in nano-metre when an electron drops from the 5th Bohr orbit to 2nd Bohr orbit in hydrogen atom?

A

217nm

B

434nm

C

651nm

D

868nm

Text Solution

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The correct Answer is:
To find the wavelength of radiation released when an electron drops from the 5th Bohr orbit to the 2nd Bohr orbit in a hydrogen atom, we can use the Rydberg formula. Here’s the step-by-step solution: ### Step 1: Write the Rydberg formula The Rydberg formula for the wavelength of emitted radiation is given by: \[ \frac{1}{\lambda} = R_H \cdot Z^2 \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right) \] where: - \(\lambda\) is the wavelength, - \(R_H\) is the Rydberg constant (\(1.09678 \times 10^7 \, \text{m}^{-1}\)), - \(Z\) is the atomic number (for hydrogen, \(Z = 1\)), - \(n_1\) is the lower energy level (2nd orbit, \(n_1 = 2\)), - \(n_2\) is the higher energy level (5th orbit, \(n_2 = 5\)). ### Step 2: Substitute the values into the formula Substituting the values into the Rydberg formula: \[ \frac{1}{\lambda} = 1.09678 \times 10^7 \cdot 1^2 \left( \frac{1}{2^2} - \frac{1}{5^2} \right) \] \[ = 1.09678 \times 10^7 \left( \frac{1}{4} - \frac{1}{25} \right) \] ### Step 3: Calculate the fractions Calculating the fractions: \[ \frac{1}{4} = 0.25 \] \[ \frac{1}{25} = 0.04 \] Now, subtract these two values: \[ 0.25 - 0.04 = 0.21 \] ### Step 4: Substitute back into the equation Now substitute back into the equation: \[ \frac{1}{\lambda} = 1.09678 \times 10^7 \cdot 0.21 \] \[ = 2.303218 \times 10^6 \, \text{m}^{-1} \] ### Step 5: Calculate \(\lambda\) Now, take the reciprocal to find \(\lambda\): \[ \lambda = \frac{1}{2.303218 \times 10^6} \approx 4.343 \times 10^{-7} \, \text{m} \] ### Step 6: Convert to nanometers To convert meters to nanometers: \[ \lambda \approx 4.343 \times 10^{-7} \, \text{m} = 434.3 \, \text{nm} \] ### Final Answer Thus, the wavelength of radiation released when the electron drops from the 5th to the 2nd Bohr orbit in a hydrogen atom is approximately: \[ \lambda \approx 434 \, \text{nm} \]

To find the wavelength of radiation released when an electron drops from the 5th Bohr orbit to the 2nd Bohr orbit in a hydrogen atom, we can use the Rydberg formula. Here’s the step-by-step solution: ### Step 1: Write the Rydberg formula The Rydberg formula for the wavelength of emitted radiation is given by: \[ \frac{1}{\lambda} = R_H \cdot Z^2 \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right) \] where: ...
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