In terms of Rydberg constant R, the shor...

In terms of Rydberg constant `R`, the shortest wavelength in the Balmer series of the hydrogen , atom spestrum will have wavelength

A

`(R )/(4)`

B

`(36R)/(5)`

C

`(5)/(36R)`

D

`(4)/(R )`

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The correct Answer is:

D

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