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The wavelength associated with a ball of...

The wavelength associated with a ball of mass 100g moving with a speed of `10^(3) cm sec^(-1) (h=6.6 xx 10^(-34)Js)` is:

A

`6.6 xx 10^(32) cm`

B

`6.6 xx 10^(-27) cm`

C

`6.6 xx 10^(27) cm`

D

`6.6 xx 10^(-32) cm`

Text Solution

AI Generated Solution

The correct Answer is:
To find the wavelength associated with a ball of mass 100g moving with a speed of \(10^3 \, \text{cm/s}\), we can use the de Broglie wavelength formula: \[ \lambda = \frac{h}{mv} \] where: - \(\lambda\) is the wavelength, - \(h\) is Planck's constant (\(6.626 \times 10^{-34} \, \text{Js}\)), - \(m\) is the mass of the object in kg, - \(v\) is the velocity of the object in m/s. ### Step 1: Convert mass from grams to kilograms The mass of the ball is given as 100g. We need to convert this into kilograms: \[ m = 100 \, \text{g} = \frac{100}{1000} \, \text{kg} = 0.1 \, \text{kg} \] ### Step 2: Convert velocity from cm/s to m/s The velocity is given as \(10^3 \, \text{cm/s}\). We need to convert this into meters per second: \[ v = 10^3 \, \text{cm/s} = 10^3 \times \frac{1}{100} \, \text{m/s} = 10^1 \, \text{m/s} = 10 \, \text{m/s} \] ### Step 3: Substitute values into the de Broglie wavelength formula Now we can substitute the values of \(h\), \(m\), and \(v\) into the de Broglie wavelength formula: \[ \lambda = \frac{h}{mv} = \frac{6.626 \times 10^{-34} \, \text{Js}}{(0.1 \, \text{kg})(10 \, \text{m/s})} \] ### Step 4: Calculate the wavelength Now we perform the calculation: \[ \lambda = \frac{6.626 \times 10^{-34}}{1} = 6.626 \times 10^{-34} \, \text{m} \] ### Final Answer The wavelength associated with the ball is: \[ \lambda = 6.626 \times 10^{-34} \, \text{m} \]
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