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Spin magnetic moment of X^(n+) (Z=26) is...

Spin magnetic moment of `X^(n+) (Z=26)` is `sqrt(24) B.M.` Hence number of unpaired electrons and value of `n` respectively are:

A

4,2

B

2,4

C

3,1

D

0,2

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The correct Answer is:
A
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