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The energy needed for Li(g) rarr Li(g)^(...

The energy needed for `Li_(g) rarr Li_(g)^(3+) + 3e` is `1. 96 xx 10^4 kJ mol ^(-1)` . If the first ionisation energy of Li is ` 520 k J mol^(-1)` . Calcuate the second ionisation energy of `Li` .
(Given : `IE_1` for ` H = 2 . 2. 18 xx 10^(-18) k J "atom"^(-1)`).

Text Solution

Verified by Experts

`Li overset(-e^(-))Li^(+) overset(e^(-)) Li^(2+) overset(e^(-))to Li^(3+)`
Total energy required `=1.96 xx 106(4)=19600"kJ mol"^(-1)`
`I.E_(1)=520kJ mol^(-1), I.E_(3)=(1312 xx Z^(2))/(n^(2))=(1312 xx 9)/(1) =11808`
`I.E_(1)+I.E_(3)=12328kJ mol^(-1)`
`I.E_(2)=19600-12328=7272"kJ mol"^(-1)`
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