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Answer the following question (Based on ...

Answer the following question (Based on `EA, Delta_(eg)H^(ɵ)` and `IE`).
(a) `IE_(1)` of `Li` is `5.4 eV "atom"^(-1)` and the `EA` of `Cl` is `3.6 eV "atom"^(-1)`. Calculate `Delta_( r)H^(ɵ)` in `"kcal mol"^(-1)` and `kJ mol^(-1)` for the reaction
`Li_((g))+Cl_((g)) rarr Li_((g))^(o+)+Cl_((g))^(ɵ)`
formed at such a low pressure that resulting ions do not combine with each other.
(b) The `IE` of atoms `X` and `Y` are `400` and `300 kcal mol^(-1)` respectively. `EA's` of these atoms are `80.0` and `85.0 K cal mol^(-1)`. Explain as which of the atoms has higher `EN`.
( c) Explain why `EA` of `S` is `-200 kJ mol^(-1)` but the second `EA` is `+649 kJ mol^(-1)`?
(d) Which of the following pairs of elements would have more negative electron gain enthalpy `(Delta_("eg")H^(ɵ))` ?
(i) `F` or `Cl` , (ii) `O` or `F`
(e) What would be the second electron gain enthalpy `(Delta_(eg)H_(2)^(ɵ))` of oxygen as positive, more negative or less negative than first `(Delta_(eg)H_(1)^(ɵ))`? Explain.
(f) Which has less negative `Delta_(eg)H^(ɵ)` oxygen or sulphur?

Text Solution

Verified by Experts

The correct Answer is:
3
Overall reaction is divided into two partial equations as
`Li(g) to Li^(+) (g) +e^(-), triangleE_(1)=5.4eV`
`Cl(g)+e^(-) to Cl^(-) (g), triangleE_(2)=-3.5eV`
`triangleH=triangleE_(1)-triangleE_(2)=1.8eV=1.8 xx 23.06 =41.508" kcal mol"^(-1)`
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