Write the geometry of `XeF_(4) and SOF_(4)` and clearly indicate the position of lone pair of electrons and hybridization of the central atom.

Explanation

To determine the geometry, hybridization, and position of lone pairs for the molecules \( \text{XeF}_4 \) and \( \text{SOF}_4 \), we can follow these steps:

### Step 1: Analyze the Valence Electrons

**For \( \text{XeF}_4 \):**
- Xenon (Xe) has 8 valence electrons.
- Each Fluorine (F) has 7 valence electrons, but since there are 4 Fluorine atoms, they collectively contribute 4 electrons to bond with Xenon.
- Total valence electrons = 8 (from Xe) + 4 (from 4 F) = 12 electrons.
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