Draw Lewis structure for `CH_(3)COOH`

Explanation

To draw the Lewis structure for acetic acid (CH₃COOH), follow these steps:

### Step 1: Determine the total number of valence electrons
- **Carbon (C)** has 4 valence electrons. There are 2 carbon atoms in CH₃COOH, so:
\(2 \times 4 = 8\) electrons.
- **Hydrogen (H)** has 1 valence electron. There are 4 hydrogen atoms in CH₃COOH, so:
\(4 \times 1 = 4\) electrons.
- **Oxygen (O)** has 6 valence electrons. There are 2 oxygen atoms in CH₃COOH, so:
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