Which among the following possesses an sp hybridized carbon in its structure ?

Options

A. `CH_(2)=C Cl -CH=CH_(2)`
B. `C.Cl_(2) =C. Cl_(2)`
C. `CH_(2)=C=CH_(2)`
D. `CH_(2) =CH-CH=CH_(2)`

Answer

To determine which among the given options possesses an sp hybridized carbon in its structure, we will analyze each option step by step.

### Step 1: Understanding Hybridization
Hybridization is a concept used to explain the bonding in molecules. The hybridization of a carbon atom can be determined by calculating its steric number, which is the sum of the number of sigma bonds and lone pairs around the carbon atom. The hybridization types are:
- **sp**: Steric number = 2
- **sp²**: Steric number = 3
- **sp³**: Steric number = 4

### Step 2: Analyze Each Option

#### Option A: CH₂=CCl-CH=CH₂
1. **Draw the structure**:
- Carbon 1: CH₂ (2 H atoms, 1 double bond with C2)
- Carbon 2: C=C (double bond with C1 and C3)
- Carbon 3: CCl (single bond with C2 and H)
- Carbon 4: CH₂ (2 H atoms, double bond with C3)

2. **Calculate steric numbers**:
- Carbon 1: 3 (2 H + 1 bond with C2)
- Carbon 2: 3 (1 bond with C1 + 1 bond with C3)
- Carbon 3: 3 (1 bond with C2 + 1 bond with Cl)
- Carbon 4: 3 (2 H + 1 bond with C3)

3. **Conclusion**: All carbons have a steric number of 3, indicating sp² hybridization.

#### Option B: CCl₂=CCl₂
1. **Draw the structure**:
- Carbon 1: CCl₂ (2 Cl atoms, 1 double bond with C2)
- Carbon 2: CCl₂ (2 Cl atoms, double bond with C1)

2. **Calculate steric numbers**:
- Carbon 1: 3 (2 Cl + 1 bond with C2)
- Carbon 2: 3 (2 Cl + 1 bond with C1)

3. **Conclusion**: Both carbons have a steric number of 3, indicating sp² hybridization.

#### Option C: CH₂=C=CH₂
1. **Draw the structure**:
- Carbon 1: CH₂ (2 H atoms, 1 double bond with C2)
- Carbon 2: C=C (double bond with C1 and C3)
- Carbon 3: CH₂ (2 H atoms, double bond with C2)

2. **Calculate steric numbers**:
- Carbon 1: 3 (2 H + 1 bond with C2)
- Carbon 2: 2 (1 bond with C1 + 1 bond with C3)
- Carbon 3: 3 (2 H + 1 bond with C2)

3. **Conclusion**: Carbon 2 has a steric number of 2, indicating sp hybridization.

#### Option D: CH₂=CH-CH=CH₂
1. **Draw the structure**:
- Carbon 1: CH₂ (2 H atoms, 1 double bond with C2)
- Carbon 2: CH (1 H atom, double bond with C1 and C3)
- Carbon 3: CH (1 H atom, double bond with C2 and C4)
- Carbon 4: CH₂ (2 H atoms, double bond with C3)

2. **Calculate steric numbers**:
- Carbon 1: 3 (2 H + 1 bond with C2)
- Carbon 2: 3 (1 H + 1 bond with C1 + 1 bond with C3)
- Carbon 3: 3 (1 H + 1 bond with C2 + 1 bond with C4)
- Carbon 4: 3 (2 H + 1 bond with C3)

3. **Conclusion**: All carbons have a steric number of 3, indicating sp² hybridization.

### Final Answer
The only option that contains an sp hybridized carbon is **Option C: CH₂=C=CH₂**.

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