Calculate the volume occupied by 7 g of nitrogen gas at `27^(@)C` and 750 mm Hg pressure

Explanation

`PV = nRT implies V = (nRT)/(P)`
Now for nitrogen, `n =(7)/(28) = (1)/(4)` mole, R = 0.082 , `T = 27^(@)C` or `27 + 273 = 300 K`
`P = (750)/(760) atm`. Now using Ideal gas equation, `PV = nRT`.
 `V=(1)/(4) xx (0.0821 xx760 xx 300)/(750)= 6.232L`