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Pressure of 1 g of an ideal gas A at 27^...

Pressure of 1 g of an ideal gas A at `27^(@)C` is found to be 2 bar, when 2 g of another gas B is introduced in the same flask at same temperature. The pressure becomes 3 bar. Find a relationship between their molecular masses.

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To solve the problem, we will follow these steps: ### Step 1: Understand the given data - Pressure of gas A (P_A) = 2 bar - Pressure of the mixture (P_total) = 3 bar - Mass of gas A (m_A) = 1 g - Mass of gas B (m_B) = 2 g - Temperature (T) = 27°C = 300 K (after conversion) ...
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