Home
Class 12
CHEMISTRY
Through the two ends of a glass tube of ...

Through the two ends of a glass tube of length `200cm` hydrogen chloride gas and ammonia are allowed to enter At what distance ammonium chloride will first appear ? .

Text Solution

Verified by Experts

`NH_(4)Cl` will appear first at a distance where HCl(g) and `NH_(3)(g)` will meet. Let after time ‘t’ they meet at a distance of ‘a’ cm from HCl end as shown below 
We now, ` (X_(HCl))/(X_(NH_(3)))= (t_(HCl))/(t_(NH_(3)))sqrt((M_(NH_(3)))/(M_(HCl)))`
Here, `X_(HCL)=acm, X_(NH_(3))=(200-a)cm, t_(HCL)=t=NH_(3)=t,M_(NH_(3))=14+3= 17,M_(HCL)= 1+35.5= 36.5` `therefore (a)/(200-a)=(t)/(t)sqrt((17)/(36.5))= 0.6824`
Solving for ‘a’ we get, a = 81.12 cm.  It means `NH_(4)Cl` will first appear at a distance of 81.12 cm from HCl end.
Promotional Banner

Similar Questions

Explore conceptually related problems

A straight glass tube has two inlets x and y at two ends. The length of the tube is 200 cm . HCl gas through inlet x and NH_(3) gas through inlet y are allowed to enter the tube at the same time. White flames first appear at a point P inside the tube. Find the distance of P from x .

A bottle of dry ammonia and a bottle of dry hydrogen chloride connected through a long tube are opened simultaneously at both ends. The white ammonium chloride ring first formed will be

At room temperature, ammonia gas at 1 atm pressure and hydrogen chloride gas at P atm pressure are allowed to effuse through identical pin holes from opposite ends of a glass tube of 1 m length and of uniform cross- section. Ammonium chloride is first formed at a distance of 60 cm from the end through which HCl gas is sent in. What is the value of P ?

A straight glass tube as shown, has 2 inleta X and Y at the two ends of 200 cm long tube. HCl gas through inlet X and NH_(3) gas through inlet Y are allowed to enter in the tube at the same time and pressure at a point P inside the tube. The distance of point P from X is: